170M3958 Eaton Bussmann 1000V 250A Class aR High Speed Fuse
170M3958 Eaton Bussmann 1000V 250A Class aR High Speed Fuse

170M3958 Eaton Bussmann 1000V 250A Class aR High Speed Fuse

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Eaton Bussmann 170M3958 — 1000V 250A Class aR high speed fuse, 100 kA interrupting. Protects semiconductors in drives, rectifiers and inverters.
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    170M3958 Eaton Bussmann 1000V 250A Class aR High Speed Fuse

    At a Glance
    • 1000 V rated voltage, 250 A rated current
    • 100 kA interrupting rating
    • Class aR time-current characteristic

    The Eaton Bussmann 170M3958 is a square body fuse with 1000 V rated voltage, 250 A rated current, 100 kA interrupting capacity, carrying a Class aR time-current characteristic.

    Specifications

    General specifications
    UPC051712678834
    EAN5704057023610
    Product Length/Depth61 mm
    Product Height72.5 mm
    Product Width43 mm
    Product Weight956 g
    Electrical data
    Amperage Rating250 A
    Voltage rating1000 V
    Voltage typeAC
    Clearing (I2T)57000 at 1000 V
    Pre arc (I2T)9550
    Watt losses55 W
    Breaking capacity100 kA
    ClassClass aR
    Product specification
    Fuse size1*
    Fitted with:Type K Indicator for micro

    Series Selection Table

    170M3958 series selection table
    Ampere ratings, dimensions and catalog numbers across the Square Body Fuse family, reproduced from the Eaton Bussmann datasheet.

    Applications

    • Industrial equipment

    Selection Notes

    • Check the voltage rating against the system voltage, and the interrupting rating against the available fault current, before specifying.

    Common Questions

    What are the ratings of the Eaton Bussmann 170M3958?
    1000 V / 250 A, with a 100 kA interrupting rating.
    How much fault current can the 170M3958 interrupt?
    100 kA. The available fault current at the installation point must not exceed this value.
    What does Class aR mean for the 170M3958?
    Class aR defines the fuse's time-current characteristic. E-rated fuses carry a defined melting curve so they coordinate predictably with upstream and downstream devices; mixing E and non-E ratings in one feeder defeats that coordination.
    How should I select the 170M3958 for a circuit?
    Match the voltage rating to the system voltage, keep the continuous current above the load current, and check that the interrupting rating exceeds the available fault current. In medium voltage work, select on the transformer or feeder fault level rather than the load current alone.

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