170M4957 Eaton Bussmann 1000V 450A Class aR High Speed Fuse
170M4957 Eaton Bussmann 1000V 450A Class aR High Speed Fuse

170M4957 Eaton Bussmann 1000V 450A Class aR High Speed Fuse

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Eaton Bussmann 170M4957 — 1000V 450A Class aR high speed fuse, 125 kA interrupting. Protects semiconductors in drives, rectifiers and inverters.
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    170M4957 Eaton Bussmann 1000V 450A Class aR High Speed Fuse

    At a Glance
    • 1000 V (IEC) rated voltage, 450 A rated current
    • 125 kA interrupting rating
    • Class aR time-current characteristic

    The Eaton Bussmann 170M4957 is a square body fuse with 1000 V (IEC) rated voltage, 450 A rated current, 125 kA interrupting capacity, carrying a Class aR time-current characteristic.

    Specifications

    General specifications
    UPC051712679497
    EAN5027590455107
    Product Length/Depth73 mm
    Product Height52 mm
    Product Width170 mm
    Product Weight576 g
    Electrical data
    Amperage Rating450 A
    Voltage rating1000 V (IEC)
    Voltage typeAC/DC
    Watt losses80 W
    Breaking capacity125 kA
    ClassClass aR
    Product specification
    Fuse size1
    Fitted with:Type K Indicator for micro

    Series Selection Table

    170M4957 series selection table
    Ampere ratings, dimensions and catalog numbers across the Square Body Fuse family, reproduced from the Eaton Bussmann datasheet.

    Applications

    • Energy and utility distribution
    • Industrial equipment
    • Photovoltaic systems

    Selection Notes

    • Check the voltage rating against the system voltage, and the interrupting rating against the available fault current, before specifying.

    Common Questions

    What are the ratings of the Eaton Bussmann 170M4957?
    1000 V (IEC) / 450 A, with a 125 kA interrupting rating.
    How much fault current can the 170M4957 interrupt?
    125 kA. The available fault current at the installation point must not exceed this value.
    What does Class aR mean for the 170M4957?
    Class aR defines the fuse's time-current characteristic. E-rated fuses carry a defined melting curve so they coordinate predictably with upstream and downstream devices; mixing E and non-E ratings in one feeder defeats that coordination.
    How should I select the 170M4957 for a circuit?
    Match the voltage rating to the system voltage, keep the continuous current above the load current, and check that the interrupting rating exceeds the available fault current. In medium voltage work, select on the transformer or feeder fault level rather than the load current alone.

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