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170M5588 Eaton Bussmann 1250V 250A Class aR High Speed Fuse
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Eaton Bussmann 170M5588 — 1250V 250A Class aR high speed fuse, 100 kAIC interrupting. Protects semiconductors in drives, rectifiers and inverters.
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170M5588 Eaton Bussmann 1250V 250A Class aR High Speed Fuse
At a Glance
- 1250 V (IEC), 1300 V (UL) rated voltage, 250 A rated current
- 100 kAIC interrupting rating
- Class aR time-current characteristic
- Top fuse status indicator
The Eaton Bussmann 170M5588 is a square body fuse with 1250 V (IEC), 1300 V (UL) rated voltage, 250 A rated current, 100 kAIC interrupting capacity, carrying a Class aR time-current characteristic. Construction is top fuse status indicator.
Specifications
General specifications
| EAN | 5027590639026 |
| UPC | 051712261708 |
| Product Length/Depth | 59 mm |
| Product Height | 74.4 mm |
| Product Width | 77 mm |
| Product Weight | 0.001 g |
Electrical data
| Amperage Rating | 250 A |
| Class | Class aR |
| Clearing (I2T) | 38500 at 1000 V, 51500 at 1250 V |
| Interrupt rating | 100 kAIC |
| Pre arc (I2T) | 6500 |
| Voltage rating | 1250 V (IEC), 1300 V (UL) |
| Watt losses | 65 W |
Product specifications
| Application | Semiconductor, DC Common bus, DC drives, power converters/rectifiers |
| Fitted with: | Type K Indicator for micro |
| Fuse indicator | Top fuse status indicator |
| Fuse size | 2 |
| Fuse type | Flush end GKN/75 Type K indicator for micro |
Series Selection Table
Applications
- Industrial equipment
Selection Notes
- Check the voltage rating against the system voltage, and the interrupting rating against the available fault current, before specifying.
Common Questions
What are the ratings of the Eaton Bussmann 170M5588?
1250 V (IEC), 1300 V (UL) / 250 A, with a 100 kAIC interrupting rating.
How much fault current can the 170M5588 interrupt?
100 kAIC. The available fault current at the installation point must not exceed this value.
What does Class aR mean for the 170M5588?
Class aR defines the fuse's time-current characteristic. E-rated fuses carry a defined melting curve so they coordinate predictably with upstream and downstream devices; mixing E and non-E ratings in one feeder defeats that coordination.
How should I select the 170M5588 for a circuit?
Match the voltage rating to the system voltage, keep the continuous current above the load current, and check that the interrupting rating exceeds the available fault current. In medium voltage work, select on the transformer or feeder fault level rather than the load current alone.
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