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170M3924 Eaton Bussmann 1000V 100A Class aR Semiconductor Fuse
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Eaton Bussmann 170M3924 — 1000V 100A Class aR semiconductor fuse, 150 kAIC interrupting. Protects semiconductors in drives, rectifiers and inverters.
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170M3924 Eaton Bussmann 1000V 100A Class aR Semiconductor Fuse
At a Glance
- 1000 V rated voltage, 100 A rated current
- 150 kAIC interrupting rating
- Class aR time-current characteristic
- Non Indicating
The Eaton Bussmann 170M3924 is a semiconductor fuse with 1000 V rated voltage, 100 A rated current, 150 kAIC interrupting capacity, carrying a Class aR time-current characteristic. Construction is non indicating.
Specifications
General specifications
| UPC | 051712678681 |
| Product Length/Depth | 61 mm |
| Product Height | 74 mm |
| Product Width | 43 mm |
| Product Weight | 392.25 g |
Electrical data
| Amperage Rating | 100 A |
| Class | Class aR |
| Clearing (I2T) | 860 at 5100 V |
| Interrupt rating | 150 kAIC |
| Voltage rating | 1000 V |
| Watt losses | 35 W |
Product specifications
| Application | DC common bus DC drives power converters/rectifiers reduced voltage starters |
| Fuse indicator | Non Indicating |
| Fuse size | 1 |
Series Selection Table
Applications
- Industrial equipment
Selection Notes
- Semiconductor fuses are chosen on I²t let-through against the device surge rating, not on continuous current alone.
Common Questions
What are the ratings of the Eaton Bussmann 170M3924?
1000 V / 100 A, with a 150 kAIC interrupting rating.
How much fault current can the 170M3924 interrupt?
150 kAIC. The available fault current at the installation point must not exceed this value.
What does Class aR mean for the 170M3924?
Class aR defines the fuse's time-current characteristic. E-rated fuses carry a defined melting curve so they coordinate predictably with upstream and downstream devices; mixing E and non-E ratings in one feeder defeats that coordination.
How should I select the 170M3924 for a circuit?
Match the voltage rating to the system voltage, keep the continuous current above the load current, and check that the interrupting rating exceeds the available fault current. In medium voltage work, select on the transformer or feeder fault level rather than the load current alone.
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