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170M5959 Eaton Bussmann 1000V 630A Class aR Semiconductor Fuse
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Eaton Bussmann 170M5959 — 1000V 630A Class aR semiconductor fuse, 125 kAIC interrupting. Protects semiconductors in drives, rectifiers and inverters.
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170M5959 Eaton Bussmann 1000V 630A Class aR Semiconductor Fuse
At a Glance
- 1000 V (IEC) rated voltage, 630 A rated current
- 125 kAIC interrupting rating
- Class aR time-current characteristic
- Centre fuse status indicator
The Eaton Bussmann 170M5959 is a fuse with 1000 V (IEC) rated voltage, 630 A rated current, 125 kAIC interrupting capacity, carrying a Class aR time-current characteristic. Construction is centre fuse status indicator.
Specifications
General specifications
| EAN | 5027590461313 |
| UPC | 051712531528 |
| Product Length/Depth | 168 mm |
| Product Height | 80 mm |
| Product Width | 124 mm |
| Product Weight | 767.25 g |
| Model Code | FUSE 630A 1000V 2BKN/75 AR UR |
Electrical data
| Amperage Rating | 630 A |
| Class | Class aR |
| Interrupt rating | 125 kAIC |
| Voltage rating | 1000 V (IEC) |
| Watt losses | 110 W |
Product specifications
| Application | Semiconductor, DC Common bus, DC drives, power converters/rectifiers |
| Fitted with: | Type K Indicator for micro |
| Fuse indicator | Centre fuse status indicator |
| Fuse size | 2 |
| Fuse type | Flush end BKN/Type K Indicator for Micro |
Series Selection Table
Applications
- Energy and utility distribution
- Industrial equipment
- Photovoltaic systems
Selection Notes
- Check the voltage rating against the system voltage, and the interrupting rating against the available fault current, before specifying.
Common Questions
What are the ratings of the Eaton Bussmann 170M5959?
1000 V (IEC) / 630 A, with a 125 kAIC interrupting rating.
How much fault current can the 170M5959 interrupt?
125 kAIC. The available fault current at the installation point must not exceed this value.
What does Class aR mean for the 170M5959?
Class aR defines the fuse's time-current characteristic. E-rated fuses carry a defined melting curve so they coordinate predictably with upstream and downstream devices; mixing E and non-E ratings in one feeder defeats that coordination.
How should I select the 170M5959 for a circuit?
Match the voltage rating to the system voltage, keep the continuous current above the load current, and check that the interrupting rating exceeds the available fault current. In medium voltage work, select on the transformer or feeder fault level rather than the load current alone.
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